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Question

Consider the quadratic equation (c5)x22cx+(c4)=0, c5. Let S be the set of all integral values of c for which one root of the equation lies in the interval (0,2) and its other root lies in the interval (2,3). Then the number of elements in S is?

A
11
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B
18
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C
10
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D
12
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Solution

The correct option is B 11
Let f(x)=(c5)c22cx+c4
f(0)f(2)<0 .................(1)
& f(2)f(3)<0 ...........................(2)
from (1) & (2)
(c4)(c24)<0
& (c24)(4c49)<0
494<c<24
s={13,14,15,.....23}
Number of elements in set S=11.
1143084_1329688_ans_d6d49a3afcb044af8bf3b187bbc2c738.jpg

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