Question

Consider the $R-L-C$ circuit given below. The circuit is driven by a $50HzAC$ source with peak voltage $220V$. If $R=400\Omega ,C=200\mu F$ and $L=6H$, the maximum current in the circuit is closest to

• A. $0.120A$
• B. $0.55A$
• C. $1.2A$
• D. $5.5A$

Answer 1

Answer: (B)

$0.55A$

At maximum current $X_c=X_L$

so Z = R

so $I=\frac{v}{R}$

so I = 0.55 A