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Question

Consider the reaction:


2X(g)+3Y(g)Z(g)

Where gases X and Y are insoluble and inert to water and Z is soluble in water, it forms a basic solution. In an experiment 3 mole each of X and Y are allowed to react in 15 L flask at 500 K. When the reaction is complete, 5 L of water is added to the flask and temperature is reduced to 300 K. The pressure in the flask is:

[Neglect aqueous tension]

A
1.64 atm
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B
2.46 atm
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C
4.92 atm
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D
3.28 atm
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Solution

The correct option is D 2.46 atm
The reaction is 2X(g)+3Y(g)Z(g).

2 moles of X react with 3 moles of Y to form 1 mole of Z.

Now 3 moles of X and 3 moles of Y are present in the flask. Y is the limiting reagent.

After reaction 1 mole of X is remaining and 1 mole of Z is formed. X is insoluble in water whereas Z is soluble in water.

Thus the pressure in the flask is due to 1 mole of X.

The total volume of a flask is 15 L. The volume of water is 5 L.

Thus the volume of gas is 155=10 L.

The ideal gas equation is PV=nRT.

Hence, P=nRTV=1×.0821×30010=2.46 atm.

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