You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Chemistry

Characteristics of Chemical Equilibrium

reaction A → ...

Question

Consider the reaction A $\to$ B, graph between half life $t_{1 / 2}$ and initial concentration (a) of the reactant is

Hence graph between $- \frac{d [A]}{d t}$ and time will be

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C
Reaction is Zero order.

Suggest Corrections

Similar questions

Q. The following graph shows how

t_{1 / 2}

(half-life) of a reactant,

R

changes with the initial reactant concentration

a_{0}

. The order of the reaction will be?

Q. The following graph shows low

t_{\frac{1}{2}}

(half life) of a reactant R changes with the initial reactant concentration

a_{0}

. The order of the reaction will be

A graph between

l o g t_{\frac{1}{2}}

and

l o g [A_{0}]

for a reaction at

27^{\circ} C

is given above. From the graph, which of the following statement(s) is/are correct?
(

t_{\frac{1}{2}}

= Half-life ;

[A_{o}]

= Initial concentration)

For which order reaction a straight line is obtained along with $x - a x i s$ by plotting a graph between half-life $(t_{1 / 2})$ and initial concentration $^{'} a^{'}$ .

Q. Give relation between half-reaction time

(t_{1 / 2})

and initial concentration of reactant for

(n - 1)

order reaction.

Join BYJU'S Learning Program

Consider the reaction A → B, graph between half life t1/2 and initial concentration (a) of the reactant is Hence graph between −d[A]dt and time will be

The correct option is C Reaction is Zero order.

Consider the reaction A $\to$ B, graph between half life $t_{1 / 2}$ and initial concentration (a) of the reactant is

Hence graph between $- \frac{d [A]}{d t}$ and time will be

The correct option is C
Reaction is Zero order.