Question

Consider the reaction,
$C_6{H}_{12}{O}_6+12H_{2}S{O}_4\to 6C{O}_2+12S{O}_2+18H_{2}O$
See the given conclusion is correct based on the given equation?
Mass ratio of $H_{2}S{O}_4$ and $C{O}_2$ in reaction mixture is $2:1$

• A. True
• B. False

Answer 1

The correct option is B False

Given reaction

$C_6{H}_{12}{O}_6+12H_2{SO}_4⟶6{CO}_2+12{SO}_2+18H_{2}O$

Here $2:1$ for $H_2{SO}_4$ and ${CO}_2$ is the moles ratio.

Where mass ratio $=\frac{2\times 98}{44}=\frac{98}{22}=\frac{49}{11}$

$\therefore$ Mass ratio of $H_2{SO}_4$ and ${CO}_2=49:11$

Hence given conclusion is false.