Question

Consider the reaction
$C_6{H}_{12}{O}_6+12H_{2}S{O}_4\to 6C{O}_2+12S{O}_2+18H_{2}O$
See the given conclusion is correct based on the given equation?
Mole ratio of $H_{2}S{O}_4$ and $C{O}_2$ in reaction mixture is $2:1$

Answer 1

Given balanced chemical equation is

$C_6{H}_{12}{O}_6+12H_2{SO}_4⟶6{CO}_2+12{SO}_2+18H_{2}O$

By this reaction is $12$ mole of $H_2{SO}_4$ reacted to get $6$ moles of ${CO}_2$

Ratio of $H_2{SO}_4$ and ${CO}_2$ in reaction mixture is $\frac{12}{6}=\frac{2}{1}=2:1$

$\therefore$ Given statement is true.