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Ways to Define Concentration

Consider the ...

Question

Consider the reaction
$C_{6} H_{12} O_{6} + 12 H_{2} S O_{4} \to 6 C O_{2} + 12 S O_{2} + 18 H_{2} O$
See the given conclusion is correct based on the given equation?
Mole ratio of $S O_{2}$ and $C O_{2}$ formed is $2 : 1$

A

True

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B

False

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Solution

The correct option is A True
Given chemical equation is
$C_{6} H_{12} O_{6} + 12 H_{2} {S O}_{4} ⟶ 6 {C O}_{2} + 12 {S O}_{2} + 18 H_{2} O$
$\to$ Moles of ${S O}_{2}$ present $= 12$
$\to$ Moles of ${C O}_{2}$ present $= 6$
Moles ratio $= \frac{12}{6} = \frac{2}{1} = 2 : 1$
$∴$ Given conclusion statement is true.

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Similar questions

Q. Consider the reaction

C_{6} H_{12} O_{6} + 12 H_{2} S O_{4} \to 6 C O_{2} + 12 S O_{2} + 18 H_{2} O

See the given conclusion is correct based on the given equation?
Mole ratio of

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Q. Consider the reaction

C_{6} H_{12} O_{6} + 12 H_{2} S O_{4} \to 6 C O_{2} + 12 S O_{2} + 18 H_{2} O

See the given conclusion is correct based on the given equation?
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C_{6} H_{12} O_{6} + 12 H_{2} S O_{4} \to 6 C O_{2} + 12 S O_{2} + 18 H_{2} O

See the given conclusion is correct based on the given equation?
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C_{6} H_{12} O_{6} + 12 H_{2} S O_{4} \to 6 C O_{2} + 12 S O_{2} + 18 H_{2} O

See the given conclusion is correct based on the given equation?
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Ways to Define Concentration

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