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Question

Consider the reaction:
Cu(s)+4HNO3(aq)2NO2(g)+Cu(NO3)2(aq)+2H2O(g)
What volume of NO2 measured at 2.0 atm and 27C can be produced by the reaction of 0.500 mol copper with excess nitric acid according to the equation above?

A
2.2 L
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B
3.1 L
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C
12 L
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D
24 L
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Solution

The correct option is A 12 L

Cu(s) + 4HNO3(aq)2NO2(g) + Cu(NO3)2(aq)+2H2O(g)

When 1 mole of copper is used, two moles of NO2 and two moles of H2O are produced.

So, for 0.5 moles of copper, 1 mole of NO2 is produced.

PV=nRT

(2)V=(1)(0.0821)(300)

V=12 L


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