Consider the reaction C2H5O-Dimethyl sulphate Me-O-O-O-S-O-Me -The leaving group is-

The correct option is A MeOSO_2O^⊝ MeOSO_2O^ #8861; is the leaving group called Mesylate ...

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Mole Concept

Consider the ...

Question

Consider the reaction $C_{2} H_{5} O^{⊝} + D i m e t h y l s u l p h a t e$

$⎛ ⎜ ⎜ ⎝ M e - O - O | | S | | O - O - M e ⎞ ⎟ ⎟ ⎠ \to$
The leaving group is:

M e O S O_{2} O^{⊝}

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M e O^{⊝}

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M e^{⊝}

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M e O S O_{2}^{⊝}

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(I) {M e}_{3} C - F H_{2} O / H^{\oplus} - ---- \to {M e}_{3} C - O H

(I I) {M e}_{3} C - F ⊖ O H - - \to {M e}_{3} C - O H

(I I I) {M e}_{3} C - C l ⊖ O H - - \to {M e}_{3} C - O H

(I V) {M e}_{3} C - M e | C | M e - C l ⊖ O H - - \to {M e}_{3} C - M e | C | M e - O H

i . M e - O | | C - O E t H_{3} O^{+} - -- \to

i i . M e - O | | C - O - O | | C - M e i i . L A H (e x c e s s) - --------- \to i i . H_{2} O

i i i . R - \oplus N \equiv ⊖ C H_{3} O^{+} - -- \to

i v . M e - O | | C - H P C C - -- \to

v . M e - O | | C - C | | O - M e H I O_{4} - -- \to

v i . C H_{3} - C H = C H - C H_{2} C H_{3} i . O_{3} - ---- \to i i . H_{2} O_{2}

(M e)_{2} S i C l_{2}

$M e_{2} S i C l_{2}$ on hydrolysis will produce

(I) {M e}_{3} C - C l ⊖ O H - - \to {M e}_{3} C - O H

(I I) F_{3} C - C H | M e - C l ⊖ O H - - \to F_{3} C - C H | M e - O H

(I I I) {M e}_{3} C - C l 90 % D_{2} O + 10 % e t h e r - ----------- \to {M e}_{3} C - O D

(I V) {M e}_{3} C - C l 90 % D_{2} O + 10 % e t h e r - ----------- \to {M e}_{3} C - O H

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