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Law of Mass Action

Consider the ...

Question

Consider the reaction
$F e^{3 +} (a q) + S C N^{-} (a q) ⇌ F e S C N^{2} (a q)$
How will the equilibrium position shift if
$F e (N O_{3})_{3} (a q)$ is added?

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Solution

Equilibrium position more to the right using up the same to the additional reactants and produce more $F e S C N^{2 +} (a q)$
Solution become a darker red colour because of the in create in concentration of $F e S C N^{2 +} (a q)$

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Similar questions

F e^{3 +} (a q) + S C N^{-} (a q) ⇌ F e S C N^{2 -} (a q)

A g N O_{3} (a q)

A g S C N

F e^{3 +} (a q) + S C N^{-} (a q) ⇌ F e S C N^{2 +} (a q)

N a O H (a q)

F e (O H)_{3}

F e^{3 +} (a q) + S C N^{-} (a q) ⇌ F e S C N^{2 -} (a q)

F e^{3 +} (a q) + S C N ⇋ F e S C N^{2 +} (a q)

F e^{3 +} (a q) + S C N^{-} (a q) ⇌ [F e (S C N)]^{2 +} (a q)

F e^{3 +}, S C N^{-}

1 \times 10^{- 3} M

8 \times 10^{- 4} M

[F e (S C N))^{2 +}

2 \times 10^{- 4} M

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