Consider the reaction given below, the products ‘X’ and ‘Y’ respectively are:

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Solution

The correct option is B
Answer: (b)
The given reaction is an aldol condensation reaction.
Initially $O H^{-}$ will abstract an $α -$ hydrogen from cyclopentanone and will form a carbanion. The carbonanion will attack the carbonyl of another molecule of cyclopentanone to form aldol.
While heating the product it undergoes $β$ -elimination to form the more substituted alkene product (stable).

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{C H}_{2} = {C H}_{2} c o l d - ------ \to d i l . {K M n O}_{4} A e x c e s s - --- \to {P C l}_{5} B

(A)

(B)

{C H}_{2} = {C H}_{2} c o l d - -------- \to d i l . K M n O_{4} A e x c e s s - --- \to P C I_{s} B

{C H}_{3} C \equiv C H 2 m o l e - ---- \to H C l A H e a t - ---- \to a q . K O H B

C H_{3} C \equiv C H a q . H_{2} S O_{4} ⟶ H g S O_{4} A P C l_{5} ⟶ H e a t B

(A)

(B)

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