Consider the reaction $N_{2} O_{4} (g) ⇌ 2 N O_{2} (g) .$ The temperature (in kelvin) at which $K_{C} = 20.4$ and $K_{P} = 600.1$ is (Round off to the Nearest Integer) Assume all gases are ideal and $R = 0.0831 L b a r K^{- 1} m o l^{- 1}$ ]

Open in App

Solution

Here change in number of gaseous moles :
$Δ n_{g} = 2 - 1 = 1$
$K_{P} = K_{C} (R T)^{Δ n_{g}}$

$600.1 = 20.4 (0.0831 \times T)^{1}$

$T = 353.99 K \approx 354 K$
Correct answer is 354

Suggest Corrections

Similar questions

Q. Consider the reaction

N_{2} O_{4} (g) ⇌ 2 N O_{2} (g) .

The temperature (in kelvin) at which

K_{C} = 20.4

and

K_{P} = 600.1

is (Round off to the Nearest Integer) Assume all gases are ideal and

R = 0.0831 L b a r K^{- 1} m o l^{- 1}

]

Q. Value of f

K_{p}

for the equilibrium reaction

$N_{2} O_{4 (g)} ⇌ 2 N O_{2 (g)}$ at 288 K is 47.9. The $K_{C}$ for this reaction at same temperature is ........(Nearest integer)

$(R = 0.083 L b a r K^{- 1} m o l^{- 1})$

Q. For the reaction

2 N O_{2 (g)} ⇌ N_{2} O_{4 (g)}, K_{p} / K_{c}

is equal to :

Q. For the following gases equilibrium

N_{2} O_{4} (g) ⇌ 2 N O_{2} (g)

K_{P}

is found to be equal to

K_{C}

. This is attained when :

Q. For the following gases equilibrium,

N_{2} O_{4} (g) ⇌ 2 N O_{2} (g), K_{p}

is found to be equal to

K_{c}

. This is attained when :

Join BYJU'S Learning Program

Consider the reaction N2O4(g)⇌2NO2(g). The temperature (in kelvin) at which KC=20.4and KP=600.1 is (Round off to the Nearest Integer) Assume all gases are ideal and R=0.0831LbarK−1mol−1]

Here change in number of gaseous moles : Δng=2−1=1 KP=KC(RT)Δng 600.1=20.4(0.0831×T)1 T=353.99K≈354K Correct answer is 354

Consider the reaction $N_{2} O_{4} (g) ⇌ 2 N O_{2} (g) .$ The temperature (in kelvin) at which $K_{C} = 20.4$ and $K_{P} = 600.1$ is (Round off to the Nearest Integer) Assume all gases are ideal and $R = 0.0831 L b a r K^{- 1} m o l^{- 1}$ ]

Here change in number of gaseous moles :
$Δ n_{g} = 2 - 1 = 1$
$K_{P} = K_{C} (R T)^{Δ n_{g}}$

$600.1 = 20.4 (0.0831 \times T)^{1}$

$T = 353.99 K \approx 354 K$
Correct answer is 354