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Question

Consider the reactions :
2S2O23(aq)+I2(s)S4O26(aq)+2I(aq)
S2O23(aq)+2Br2(l)+5H2O(l)2SO24(aq)+4Br(aq)+10H+(aq)
Why does the same reductant, thiosulphate react differently with iodine and bromine ?

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Solution

Br2 is better oxidising agent than I2 hence, Br2 oxidises sulphur to its maximum oxidation state that is +6 while I2 does not. This is because Br2 is more electromagnetic than I2. Hence it easily gets converted to Br.

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