Question

Consider the reactions: $A\to B,B\to 2C,3C\to 4D$. The number of moles of $D$ formed starting with 4 mol of $A$ are:

• A. 8.17 mol
• B. 16.48 mol
• C. 4.26 mol
• D. 10.67 mol

Answer 1

The correct option is D 10.67 mol

1 mol of A produces 1 mol of B.
So, 4 mol of A will produce 4 mol of B.
In 2nd reaction, 1 mol of B produces 2 mol of C.
So, 4 mol of B will produce 8 moles of C.
In 3rd reaction, 3 mol of C produce 4 mol of D.
So, 8 mol of C will produce $\frac{4}{3}\times 8=10.67\text{mol}$