Consider the reactions (i) (CH3)2CH−CH2BrC2H5OH−−−−−→(CH3)2CH−CH2OC2H5+HBr (ii) (CH3)2CH−CH2BrC2H5O−−−−−−→(CH3)2CH−CH2OC2H5+Br− The mechanisms of reactions (i) and (ii) are respectively:
A
SN1 and SN2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
SN1 and SN1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
SN2 and SN2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
SN2 and SN1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is BSN1 and SN2 C2H5OH being a weaker nucleopbile, when used as a solvent in case of hindered 1∘ halide, favours SN1 mechanism while C2H5O− being a strong nucleophile in this reaction favours SN2 mechanism.