Question

Consider the rectangle ABCD in the figure where
$DE=\frac{1}{3}DC$


The area of the triangle ADE is $20c{m}^2$, then what will be the area of the rectangle ABCD?

• A.
  $60c{m}^2$
• B.
  $80c{m}^2$
• C.
  $100c{m}^2$
• D.
  $120c{m}^2$

Answer 1

The correct option is D

$120c{m}^2$
$\Delta ADE=\frac{1}{2}\times x\times h=20\left(\text{given}\right)$
$x\times h=40$

$\Rightarrow 3x\times h=3\left(xh\right)=3\left(40\right)=120c{m}^2$