Consider the sequence defined recursively by p 1- a any positive integer- and p n -1-1- p n -1- n -1-2-3 For which of the following values of n must Pn - a -A- 18B- 19C- 14D- 15

The correct option is B 19 p_1=a; p_2= 1/a+1;p_3=( 1 1/a);p_4=a. Hence the pattern p_1=p_4=p_7=p_10=p_13=p_16= p_19....=a Hence, choice (c) is the right answe ...

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Consider the sequence defined recursively by $p_{1} = a$ (any positive integer), and $p_{n + 1} = - \frac{1}{p_{n} + 1}$ , n=1,2,3 For which of the following values of n must
$p_{n}$ =a?

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Solution

The correct option is C
19

$p_{1} = a; p_{2} = \frac{- 1}{a + 1}; p_{3} = (- 1 - \frac{1}{a}); p_{4} = a .$

Hence the pattern $p_{1} = p_{4} = p_{7} = p_{10} = p_{13} = p_{16} = p_{19} . . . . = a$
Hence, choice (c) is the right answer

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Consider the sequence defined recursively by p1=a (any positive integer), and pn+1=−1pn+1, n=1,2,3 For which of the following values of n must pn=a?

The correct option is C 19 p1=a; p2=−1a+1;p3=(−1−1a);p4=a. Hence the pattern p1=p4=p7=p10=p13=p16=p19....=a Hence, choice (c) is the right answer

Consider the sequence defined recursively by $p_{1} = a$ (any positive integer), and $p_{n + 1} = - \frac{1}{p_{n} + 1}$ , n=1,2,3 For which of the following values of n must
$p_{n}$ =a?

The correct option is C
19

$p_{1} = a; p_{2} = \frac{- 1}{a + 1}; p_{3} = (- 1 - \frac{1}{a}); p_{4} = a .$

Hence the pattern $p_{1} = p_{4} = p_{7} = p_{10} = p_{13} = p_{16} = p_{19} . . . . = a$
Hence, choice (c) is the right answer