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Question

Consider the sequence of number [n+2n+12] for n1, where [x] denotes the greatest integer not exceeding x. If the missing integers in the sequence are n1<n2<n3< then find the n12.

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Solution

Sn=n+[2n+0.5], n1
where, [n]= Greatest integer less than n.

n2n[2n+0.5]n+[2n+0.5]11.412222432.42542.83753.13863.43973.74118441294.2413104.4414114.7516124.9517135.1518145.3519155.4520165.6622175.8623186624196.1625206.3626216.4627226.6729
By observing pattern,
Missing numbers =
12th number in series =78

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