Solution:
(i) A = {..., -3, -2, -1, 0, 1, 2, 3,...}
D = {1, 2, 3,...}
A ∪ D = {..., -3, -2, -1, 0, 1, 2, 3,...} = A
As A ∪ D = A and every set is a subset of itself, therefore, A is subset of A ∪ D.
Hence, the given statement is true.
[1 Mark]
(ii) D = {1, 2, 3,...}
B ∪ C = {.....-10, -8, -5, -4, 0, 4, 5, 8, 10, 12, 15,....}
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∴ D is not a subset of B ∪ C.
Hence, the given statement is false.
[1 Mark]