Question

Consider the shear force diagram shown in given figure


The loaded beam will be

• A.
• B.
• C.
• D.

Answer 1

The correct option is A

(a)

The slope of shear force diagram can be used to find load intensity.

$\frac{dV}{dx}=-w$

For point loads and reaction, there is sudden change in shear force at point of application. Support at A = 14t
There is no load between A and D as SFD does not change. At D there is sudden change in value of SF from 14t to -4 t. So there is point load of 18 t at point D. Between D and B the shape of SFD is linearly decreasing so there is uniformly distributed load between B and D. The intensity of UDL is
$w=\frac{16-4}{8}=\frac{12}{8}=1.5t/m$
At B there is sudden change in the SF so there is reaction at $R_B=16+9=25t$
Again between B and C the SFD decreases linearly from 9 t to 3 t. So load intensity

$w=\frac{9-3}{4}=1.5t/m$

Finally the SFD decreases to zero suddenly at C. So a point load of 3 t is applied at C.