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Question

Consider the situation as shown in figure. A constant force acting on the lower blocks produces an acceleration of 4 m/s2. The two blocks always move together. Find the work done by static friction on the upper block during displacement 2 m of the system.


A
8 J
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B
Zero
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C
16 J
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D
10 J
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Solution

The correct option is C 16 J
By the FBD of 2 kg body, there will be only frictional force in the forward direction for the block to move forward
with acceleration, a=4 m/s2


Now since the whole system is moving at a=4 m/s2 and fs is the only force in 2 kg body

By Newton's 2nd law

fs=ma=2×4=8 N, (As both blocks move together)

Work done by static friction on upper block =fs.S
As displacement is given as (S=2 m)
W=8×2
W=16 J

Hence option C is the correct answer

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