Consider the situation depicted in the adjacent figure. The work done in taking a point charge from P to A is WA, from P to B is WB and from P to C is WC. Therefore,
A
WA<WB<WC
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B
WA>WB>WC
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C
WA=WB=WC
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D
WA>WB<WC
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Solution
The correct option is CWA=WB=WC The potential at the surface of the sphere is same i.e. RQR. It behaves as an equipotential surface. Hence, work done along all path is same i.e. WA=WB=WC.