Consider the situation in figure- The bottom of the pot is a reflecting plane mirror- S is a small fish and T is human eye- Refractive index of water is -a At what distances from itself will the fish see the images of the eye -b At what distances from itself will the eye see the images of the fish-

As shown in the given figure, sin 45^∘/sin r=2/1 ⇒ sin r=sin 45^∘/sin r=1/2√(2) ⇒ =21^∘ ∴θ =(45^∘ 21^∘) =24^∘ = 0.406 × AB sin 24^∘ =0.406 × AB =AE/cos 21^∘× 0. ...

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Byju's Answer

Standard XII

Physics

Pascal's Law

Consider the ...

Question

Consider the situation in figure. The bottom of the pot is a reflecting plane mirror, S is a small fish and T is human eye. Refractive index of water is $μ$ .

(a) At what distance(s) from itself will the fish see the image(s) of the eye ?

(b) At what distance(s) from itself will the eye see the image(s) of the fish.

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Solution

a) At what distance(s) from itself will the fish see the image(s) of the eye
1) Direct observation by fish
$H_{1} = \frac{H}{2} + μ H = H (\frac{1}{2} + μ)$
2) Fish observing the image of the eye in the mirror.
$H_{2} = μ H + H + \frac{H}{2} = H (μ + \frac{3}{2})$
b) Observation of fish by the eye-
1) Direct observation
$H_{3} = H + \frac{H}{2 μ} = H (1 + \frac{1}{2 μ})$
2) Observation in the plane mirror
$H_{4} = H + \frac{H}{μ} + \frac{H}{2 μ} = H (1 + \frac{3}{2 μ})$

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