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Consider the situation shown in figure (17-E6). The two slits S1 and S2 placed symmetrically around the central line are illuminated by a monochromatic light of wavelength λ the separation between the slits is d. The light transmitted by the slits falls on a screen 1 placed at a distance D from the slits. The slitS3 is at the central line and the slit S4 is at a distane z rom S3 Another screen 2 is palced a further distance D away from 1 find the ration of thmaximum to minimum intensity obsered on 2 if z is equal to
(a) z=λD2d
(b) λd,
(c) λD4d.


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    Solution

    (i) When z=Dλ2d,atS4
    Minimum ntensity occurs, (dark fringe)
    Aplitude=0

    At S3 pat difference = 0
    Maximum intensity occurs.
    Amplitude = 2r
    So, on 2 screen,
    lmaxlmin=(2r+0)2(2r0)2=1
    (ii) When, z=λDd
    At S4 maximum ntensity occurs.
    Amplitude=2r
    At S3 also maximum ntensity occurs.
    lmaxlmin=(2r+2r)2(2r2r)2=(iii)when,Z=λD4d,AtS4
    Intensity =lmax2
    Amplitude =2r
    At S3 Intesnsity is minimum.
    Amplitude = 2r
    lmaxlmin=(2r+2r)2(2r2r)2=34


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