CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Consider the situation shown in figure (31-E23). The switch S is open for a long time and then closed. (a) Find the charge flown through the battery when the switch S is closed. (b) Find the work done by the battery.



(c) Find the change in energy stored in the capacitors.
(d) Find the heat developed in the system.

Open in App
Solution

Since the switch is opened for a long time, the capacitor is in series.
Ceq=C2

When the switch is closed, the charge flown from the battery is given by

q=C2×ε=Cε2

(b) Work done, W=q×V
q=Cε2×ε=Cε22

(c) The change in the energy stored in the capacitors is given by
E=12 Ceq×v2 =12×C2×ε2=14 Cε2

(d) The heat developed in the system is given by

H=EH=14 Cε2

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Recap of Work Done in a Conservative Field
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon