Consider the situation shown in figure. Initially, the spring is unstretched when the mass m is released from rest. Assuming no friction in the pulley, find the maximum extension in the spring.
A
mgk
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B
mg2k
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C
2mgk
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D
4mgk
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Solution
The correct option is Amgk
At the maximum extension, mass m must finally come to rest. Therefore, ΔK.E=0
Wext=ΔK.E+ΔU There is no external force on the system So, for maximum extension in the spring, ΔU=0 Loss in gravitational P.E of mass = Gain in elastic P.E energy of spring
From string constraint on pulley, extension of spring = 2× displacement of mass ΔU=0 ⇒12kx2=mgx2 ⇒x=mgk