(a)
The acceleration is given as,
T+Ma−Mg=0
Ma2+Ma−Mg=0
a=2g3
(b)
The tension is given as,
T=Ma2
T=M×2g32
T=Mg3
(c)
Let the resultants of the tension is R.
It can be written as,
R′=√T2+T2
R′=√2Mg3
The angle is given as,
tanθ=TT
θ=45∘
Thus, the force exerted by the clamp on the pulley is √2Mg3 at an angle of 45∘ with horizontal.