Consider the situation shown in the figure. The capacitor A has charge $q$ on it, whereas B is uncharged. The charge appearing on the capacitor B a long time after the switch S is closed is $\frac{n q}{2}$ , where $n$ is

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Solution

When switch S is closed, there is no transfer of charge from capacitor A to capacitor B because the charge $- q$ of A is held by its charge $+ q$ .

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