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Standard XII

Physics

Idea behind a PPC

Consider the ...

Question

Consider the situation shown in the figure. The capacitor A has charge q on it, whereas B is uncharged. The charge appearing on the capacitor B a long time after the switch S is closed, is:

Z e r o

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\frac{q}{2}

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q

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2 q

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Solution

The correct option is A $Z e r o$
When switch S is closed, there is no transfer of charge from capacitor A to capacitor B because the charge –q of A is held by its charge +q.

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Consider the situation shown in the figure. The capacitor A has charge q on it, whereas B is uncharged. The charge appearing on the capacitor B a long time after the switch S is closed, is:

The correct option is A ZeroWhen switch S is closed, there is no transfer of charge from capacitor A to capacitor B because the charge –q of A is held by its charge +q.

The correct option is A $Z e r o$
When switch S is closed, there is no transfer of charge from capacitor A to capacitor B because the charge –q of A is held by its charge +q.