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Question

Consider the situatuion shown in figure. A plane mirror is fixed at a height h above the bottom of a beaker containing water (refractive index μ ) up to a height d. Find the position of the image of the bottom formed by the mirror.

A
hd+dμ.
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B
h+d+dμ.
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C
hddμ.
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D
d+dμ.
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Solution

The correct option is A hd+dμ.
The bottom of the beaker appears to be shifted up by a distance
t=(11μ)d.

Thus, the apparent distance of the bottom from the mirror is ht=h(11μ)d=hd+dμ. The image is formed behind the mirror at a distance hd+dμ.

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