Consider the statement:
"Not all that glitters is gold"
Predicate glitters(x) is true if x glitters and predicate gold(x) is true if x is gold. Which one of the following logical formulae represents the above statement?
A
∀x:glitters(x)⇒¬gold(x)
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B
∀x:gold(x)⇒¬glitters(x)
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C
∃x:gold(x)∧¬glitters(x)
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D
∃x:glitters(x)∧¬ gold(x)
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Solution
The correct option is D∃x:glitters(x)∧¬ gold(x) (a) ∀xglitters(x)⇒¬gold(x)
All glitters are not gold
(b) ∀xgold(x)⇒glitters(x)
All golds are glitters
(c) ∃xgold(x)∧¬glitters(x)
There exist gold which is not glitter i.e. not all golds are glitters.
(d) ∃xglitters(x)∧¬ gold(x)
Not all that glitters is gold i.e., there exist some which glitters and which is not gold.