Question

Consider the straight lines $x+2y+4=0$ and $4x+2y-1=0$. The line $6x+6y+7=0$ is :

• A. bisector of the angle including origin
• B. bisector of acute angle
• C. bisector of obtuse angle
• D. none of these

Answer 1

Answer: (A), (B)

The correct options are
A bisector of the angle including origin
B bisector of acute angle

by formula
$\frac{x+2y+4}{\sqrt{1^2+2^2}}=-\frac{4x+2y-1}{\sqrt{4^2+2^2}}$
$6x+6y+7=0$
we used (-) sign for calculating bisector, so this bisector is for acute angle.