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Coordinate Bond

Consider the ...

Question

Consider the structure of $A l_{2} M e_{6}$ compound and find the value of $\frac{x - y}{z}$ , where:
$x =$ Maximum number of atoms that can lie in plane having terminal $(A l - M e)$ bonds.
$y =$ Total number of $3 c - 2 e^{-}$ bonds.
$z =$ Total number of atoms that are $s p^{3}$ hybridized.

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Solution

Have 2 $3 C - 2 e$ bonds ( y = 2 )

Number of atoms lying on a plane having terminal are = ( x = 10 )

Number of $s p^{3}$ hybridised atoms are = ( z = 8 )

So value of $\frac{x - y}{z} = \frac{10 - 2}{8} = 1$

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