Consider the system shown in figure. System is released from rest, find the tension (in Newton) in the cord connected between 1 kg and 2 kg blocks. (g=10ms2)
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Solution
By Newton's second law, we have 1g−T1=1a...........(i) (T1+2g)−T2=2a...........(ii)
and T2−2g=2a...........(iii)
Solving equation (i), (ii) & (iii), we get a=2ms2 T1=8N