Consider the table given below
Marks 0-10 10-20 20-30 30-40 40-50 50-60
Number of Students 12 18 27 20 17 6
The arithmetic mean of the marks given above is

18

No worries! We‘ve got your back. Try BYJU‘S free classes today!

28

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

27

No worries! We‘ve got your back. Try BYJU‘S free classes today!

6

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $28$
$x_{i} = \frac{upper limit + lower limit}{2}$

Marks No. of students
$(f_{i})$ $x_{i}$ $x_{i} f_{i}$
0-10 12 5 60
10-20 18 15 270
20-30 27 25 675
30-40 20 35 700
40-50 17 45 765
50-60 6 55 330
$Σ f_{i} = 100$ $Σ x_{i} f_{i} = 2800$
$∴ M e a n = \frac{Σ x_{i} f_{i}}{Σ f_{i}} = \frac{2800}{100} = 28$
Hence, the option $(B)$ is correct

Suggest Corrections

Similar questions

Marks	0 - 10	10 - 20	20 - 30	30 - 40	40 - 50	50 - 60
Number of students	8	7	13	12	30	25

If the arithmetic mean of the data given below is 28, find (a) the missing frequency, and (b) the median of the series:

Profit per retail shop (in Rs)	0 – 10	10 – 20	20 – 30	30 – 40	40 – 50	50 – 60
Number of retail shops	12	18	27	–	17	6

Marks	No. of students
0 - 10 10 - 20 20 - 30 30 - 40 40 - 50 50 - 60	5 10 25 30 20 10

Marks:	0-10	10-20	20-30	30-40	40-50	50-60
Number of students:	7	10	23	51	6	3

Age in years	0 - 10	10 - 20	20 - 30	30 - 40	40 - 50	50 - 60
Number of patients	16	13	6	11	27	18

Join BYJU'S Learning Program