Consider the transistor circuitt shown in the figure below:
The value of Vin is chosen such that the output voltage V0 is equal to 6 V. Then the value of Vin is equal to (Assume,VBE(ON))=0.7V
A
3.97 V
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
4.21 V
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
5.21 V
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
3.11 V
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is A 3.97 V Now,IC=12−62.2×−3=2.727mA ∴IB=ICβ=2.72730=111mA Now,I2=0.7−(−12)100kΩ=0.127mA ∴I1=I2+IB=0.218mA thus,Vin=I1×15×103Ω+0.7 Vin=3.968V=3.97V