Consider the triangle $A B C$ with vertices $A (- 2, 3), B (2, 1)$ and $C (1, 2)$ .
What is the centroid of the triangle $A B C$ ?

(\frac{1}{3}, 1)

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(\frac{1}{3}, 2)

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(1, \frac{2}{3})

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(\frac{1}{2}, 3)

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Solution

The correct option is B $(\frac{1}{3}, 2)$
Given : $A (- 2, 3), B (2, 1)$ and $C (1, 2)$
Centroid of the triangle $= (\frac{- 2 + 2 + 1}{3}, \frac{3 + 1 + 2}{3}) = (\frac{1}{3}, 2)$

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