Consider the two curves C1:y2=4x, C2:x2+y2−6x+1, then
A
C1 and C2 touch each other only at one point.
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B
C1 and C2 touch each other exactly at two points
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C
C1 and C2 intersect (but do not touch) at exactly two points,
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D
C1 and C2 neither intersect nor touch each other.
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Solution
The correct option is BC1 and C2 touch each other exactly at two points Solving the two equations, we get x2+4x−6x+1=0 ⇒x2+2x+1=0 ⇒x=1 and y=±2 So the two curves meet at two points (1,2) and (1,−2). Equation of the tangent at (1,2) to C1 is y(2)=2(x+1) ⇒y=x+1 and Equation of the tangent at (1,2) to C2 is x.1+y(2)−3(x+1)+1=0⇒y=x+1 Showing that C1 and C2 have a common tangent at the point (1,2). Similarly they have a common tangent y=−(x+1)at(1,−2) Hence, the two curves touch each other exactly at two points.