Question

Consider the word ${}^{\prime }PERMUTATIO{N}^{\prime }$. How many permutations can be made such that a word should always start with a vowel?

• A. $\frac{5\times 10!}{2}$
• B. $\frac{10!}{2!}$
• C. $5!\times 6!$
• D. none of these

Answer 1

The correct option is A $\frac{5\times 10!}{2}$

${}^5{C}_1$ Ways $=5$

Rest $10$ blanks $⟶10$ letters

Number of ways $=\frac{10!}{2!}$ Ways

(Therefore $T$ is repeated twice )

Total number of ways $=\frac{5!\times 10!}{2!}$ ways