Consider the word $^{'} P E R M U T A T I O N^{'}$ .
How many words can be formed by using all the letters of the given word?

\frac{11!}{2!}

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9! \times 2!

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11!

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none of these

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Solution

The correct option is A $\frac{11!}{2!}$
The word "PERMUTATION" has $2$ Ts while other letters are distinct.
Number of words $= \frac{11!}{2!}$

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P E R M U T A T I O N

T

^{'} P E R M U T A T I O N^{'}

M

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