Question

Consider the YDSE arrangement shown here.
If $\lambda =0.25d$, number of maxima formed on the screen is ?

• A. $4$
• B. $9$
• C. $8$
• D. $7$

Answer 1

The correct option is A $4$

Given,

$\lambda =0.25d$

We know that

$d\sin \theta =n\lambda$

For number of maxima found on the screen $\sin \theta =1$

$n=\frac{d}{\lambda }$

Here, $n$ is number of fringe,$\lambda$ is wavelength and $d$ is distance between slit.

$n=\frac{d}{0.25d}=4$

Number of maxima is $4$

correct option is A.