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Transistor as an Amplifier

Consider the ...

Question

Consider the Zener voltage regulator shown in the figure below.The zener diode has
$V_{z} = 10 V, I_{z (min)} = 5 m A a n d I_{z (max)} = 24 m A .$
The range of value of the load current $I_{L}$ is

6mA to 25 mA

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2 mA to 30 mA

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5mA to 24 mA

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5 mA to 20 mA

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Solution

The correct option is A 6mA to 25 mA
(c)
$I_{i n} = \frac{V_{i n} - V_{Z}}{1 k} = \frac{40 - 20}{1 k} = 30 m A$

$I_{i n} = I_{Z} + I_{L}$

$I_{L (min)} = I_{i n} - I_{Z (max)} = 30 - 24 = 6 m A$

$I_{L (max)} = I_{i n} - I_{Z (min)} = 30 - 5 = 25 m A$

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