You visited us 68 times! Enjoying our articles? Unlock Full Access!

Transistor as an Amplifier

Consider the ...

Question

Consider the Zener voltage regulator shown in the figure below.The zener diode has
$V_{z} = 10 V, I_{z (min)} = 5 m A a n d I_{z (max)} = 24 m A .$
The range of value of the load current $I_{L}$ is

6mA to 25 mA

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

2 mA to 30 mA

No worries! We‘ve got your back. Try BYJU‘S free classes today!

5mA to 24 mA

No worries! We‘ve got your back. Try BYJU‘S free classes today!

5 mA to 20 mA

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A 6mA to 25 mA
(c)
$I_{i n} = \frac{V_{i n} - V_{Z}}{1 k} = \frac{40 - 20}{1 k} = 30 m A$

$I_{i n} = I_{Z} + I_{L}$

$I_{L (min)} = I_{i n} - I_{Z (max)} = 30 - 24 = 6 m A$

$I_{L (max)} = I_{i n} - I_{Z (min)} = 30 - 5 = 25 m A$

Suggest Corrections

Similar questions

R_{L}

k Ω .

I_{L}

I_{z (m i n)} = 1 m A)

V_{Z} = 10 V, R_{Z} = 0 Ω, R = 450 Ω, I_{Z} (m i n) = 2 m A

I_{Z} (m a x) = 60 m A

10 V

(R_{s})

200 Ω

V_{z} = 5 V

R_{s}

R_{L} = 4 k Ω

R_{i} = 1 k Ω

V_{B}

8 V

16 V

Join BYJU'S Learning Program