Consider this calendar. Select the numbers 1, 2, 3, 8, 9, 10, 15, 16, 17 such that they form a square. The sum of the selected numbers of the square, is ____ times the middle number of the square.

9

Open in App

Solution

The correct option is A 9
Sum of the selected numbers
= 1 +2 + 3+ 8 + 9 + 10 + 15 +16 +17
= 81

If the central number is x, we can fill in the other numbers in the way displayed above.

Sum of these numbers would be
= x - 8 + x - 7 + x - 6 + x - 1 + x + x + 1 + x + 6 + x + 7 + x + 8
= 9x

Hence, sum of all the 9 numbers = 9 times the central number.

Suggest Corrections

Similar questions

Consider this calendar. Select the numbers 4,5,6,11,12,13,18,19,20 such that they form a square. The sum of the selected numbers of the square, is ____ times the middle number of the square.

Q. The number of ways to select

2

numbers from

0, 1, 2, 3, 4

such that the sum of the square of the selected number is divisible by

5

are (repetition of digits is allowed ).

Consider the following calendar.

Consider any four numbers which form a square as shown below.

The difference between the product of the diagonal numbers will be equal to

Consider the following calendar.

The Nine numbers form a square as shown below.

The difference between the product of the diagonal numbers will be equal to

Q. Given is image of a calendar. The sum of numbers enclosed in the square is

Join BYJU'S Learning Program

Consider this calendar. Select the numbers 1, 2, 3, 8, 9, 10, 15, 16, 17 such that they form a square. The sum of the selected numbers of the square, is ____ times the middle number of the square. 9

Consider this calendar. Select the numbers 1, 2, 3, 8, 9, 10, 15, 16, 17 such that they form a square. The sum of the selected numbers of the square, is ____ times the middle number of the square.

9