Question

Consider three mixtures - the first having water and liquid A in the ratio 1:2, the second having water and liquid B in the ratio 1:3, and the third having water and liquid C in the ratio 1:4. These three mixtures of A, B, and C, respectively, are further mixed in the proportion 4:3:2. Then the resulting mixture has

• A. The same amount of water and liquid B
• B. The same amount of liquids B and C
• C. More water than liquid B
• D. More water than liquid A

Answer 1

The correct option is C

More water than liquid B

Converting words into numbers, we get
Liquid 1 (L1) - W : A = 1 : 2
Liquid 2 (L2) - W : B = 1 : 3
Liquid 3 (L3) - W : C = 1 : 4
Liquids are mixed in the ratio of L1 : L2 : L3 = 4 : 3 : 2
Multiplying the ratio with LCM of 3, 4, and 5 which is 60
L1 : L2 : L3 = 240 : 180 : 120
Quantity of water in the mixture = $\frac{1}{2}\times 240+\frac{1}{4}\times 180+\frac{1}{5}\times 120$ = 120 + 45 + 24 = 189
Quantity of total mixture = 240 + 180 + 120 = 540
Concentration of water in the final solution = $\frac{135}{540}$ = 7/20 = 0.35, which is greater than $\frac{1}{3}$
Hence, concentration of water in the final mixture is more than that in the sample B.