Consider three vectors →A=^i+^j−2^k,→B=^i−^j+^k and →C=2^i−3j+4^k.A vector →X of the form α→A+β→B (α and β are numbers) in perpendicular to →C. The ratio of α and β is
A
1:1
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B
2:1
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C
−1:1
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D
3:1
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Solution
The correct option is A1:1 α→A=α^i+α^j−2α^k
β→B=β^i−β^j+β^k
Hence (α→A+β→B).→C=[(α+β)^i+(α−3β)^j+(−2α+4β)^k].(2^i−3^j+4^k)=0(Since they are perpendicular)