Consider two buses connected by an impedance of 0-j5- The bus 1 voltage is 100-30-V- and bus 2 voltage is 100-0-V- The real and reactive power supplied by bus 1- respectively are

V_1=100 ∠30^∘V and nbsp; V_2=100∠0^∘V as δ_1 gt;δ_2, current will flow from bus 1 to 2 Z=0+j5 Ω I=V_1 V_2Z =100∠30^∘ 100∠0^∘j5 =10.35∠15^∘A Complex pow ...

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Consider two buses connected by an impedance of $(0 + j 5) Ω$ . The bus 1 voltage is $100 ∠ 30^{\circ} V$ , and bus 2 voltage is $100 ∠ 0^{\circ} V$ . The real and reactive power supplied by bus 1, respectively are

1000 W, 268 VAR

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-1000 W, -134 VAR

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276.9 W, 56.7 VAR

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-276.9 W, 56.7 VAR

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Solution

The correct option is A 1000 W, 268 VAR
$V_{1} = 100 ∠ 30^{\circ} V$ and $V_{2} = 100 ∠ 0^{\circ} V$
as $δ_{1} > δ_{2}$ , current will flow from bus 1 to 2

$Z = 0 + j 5 Ω$

$I = \frac{V_{1} - V_{2}}{Z}$

$= \frac{100 ∠ 30^{\circ} - 100 ∠ 0^{\circ}}{j 5}$

$= 10.35 ∠ 15^{\circ} A$

Complex power $= S = P + j Q = V_{1} I$

$P + j Q = 100 ∠ 30^{\circ} \times (10.35 ∠ 15^{\circ})$

$= 1000 + j 268$

$P = 1000 W$ and $Q = 268 V A R$

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Consider two buses connected by an impedance of (0+j5)Ω. The bus 1 voltage is 100∠30∘V, and bus 2 voltage is 100∠0∘V. The real and reactive power supplied by bus 1, respectively are

The correct option is A 1000 W, 268 VARV1=100∠30∘V and V2=100∠0∘V as δ1>δ2, current will flow from bus 1 to 2 Z=0+j5Ω I=V1−V2Z =100∠30∘−100∠0∘j5 =10.35∠15∘A Complex power =S=P+jQ=V1I P+jQ=100∠30∘×(10.35∠15∘) =1000+j268 P=1000W and Q=268VAR

Consider two buses connected by an impedance of $(0 + j 5) Ω$ . The bus 1 voltage is $100 ∠ 30^{\circ} V$ , and bus 2 voltage is $100 ∠ 0^{\circ} V$ . The real and reactive power supplied by bus 1, respectively are