Consider two concentric spherical shells of radius R and 2R; with same surface charge density. If total charge on them is Q, then find electric potential at their centre.

$\frac{k Q}{R}$

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$\frac{k Q}{2 R}$

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$\frac{2 k Q}{R}$

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$\frac{3 k Q}{5 R}$

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Solution

The correct option is D
$\frac{3 k Q}{5 R}$

$Q = σ (4 π R^{2} + 4 π (2 R)^{2}) Q = 20 π σ R^{2} N o w, V = \frac{k q_{1}}{R} + \frac{k q_{2}}{2 R} V = \frac{k}{R} [σ 4 π R^{2} + \frac{σ 16 π R^{2}}{2}] V = \frac{3 k Q}{5 R}$

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Consider two concentric spherical shells of radius R and 2R; with same surface charge density. If total charge on them is Q, then find electric potential at their centre.

The correct option is D 3kQ5R Q=σ(4πR2+4π(2R)2)Q=20πσR2Now,V=kq1R+kq22RV=kR[σ4πR2+σ16πR22]V=3kQ5R

The correct option is D
$\frac{3 k Q}{5 R}$

$Q = σ (4 π R^{2} + 4 π (2 R)^{2}) Q = 20 π σ R^{2} N o w, V = \frac{k q_{1}}{R} + \frac{k q_{2}}{2 R} V = \frac{k}{R} [σ 4 π R^{2} + \frac{σ 16 π R^{2}}{2}] V = \frac{3 k Q}{5 R}$