Consider two covalent compounds $A L_{n 1}$ and $B L_{n 2}$ . If central atom $(A)$ of first compound has total of six valence electron pairs and central atom $(B)$ of second compound contains total of five valence electron pairs and both compounds are planar and non-polar then calculate value of expression $(n_{1} - n_{2})^{2}$ .
[where $n_{1}$ and $n_{2}$ are number of monovalent surrounding atom $(L)$ ]

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Solution

$in A L_{n 1} :$
$Number of valence electron pairs on A = 6$
$Given, it is non-polar and planar$
$Thus possible shape is sqare planar$
$Hence, n_{1} = 4$
${In BL}_{n 2} :$
$Number of valence electron pairs on B = 5$
$Given, it is non-polar and planar$
$Thus possible shape is linear$
$Hence, n_{2} = 2$
$∴ (n_{1} - n_{2})^{2} = (4 - 2)^{2} = 4$

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in ALn1: Number of valence electron pairs on A=6 Given, it is non-polar and planar Thus possible shape is sqare planar Hence, n1=4 In BLn2: Number of valence electron pairs on B=5 Given, it is non-polar and planar Thus possible shape is linear Hence, n2=2 ∴(n1−n2)2=(4−2)2=4