Consider two functions defined on R as f(x) = 2 + |x – 1| and g(x) = min (f(t)) where x≤t≤x2+x+1. If n1 denotes number of points of discontinuity of g(x) and n2 denotes number of points where g(x) is non-differentiable then (n1+n2) is equal to
3
3
f(t)={3−t;t≤1t+1;t>1
Now, g(x)=⎧⎪⎨⎪⎩3−(x2+x+1);xϵ[−1,0]2;xϵ(−∞,−1)∪(0,1)x+1;xϵ[1,∞)∴ n1=0,n2=3⇒(n1+n2)=3